A point charge 5C located at 3jm .find the electrostatic force due to the given point charge configuration.125nC at -4jm and 125nC at 4im
To find the electrostatic force due to the given point charge configuration, we can consider each pair of charges individually.
First, let's find the force between the 5C charge at 3jm and the 125nC charge at -4jm:
Distance between the two charges = 3jm - (-4jm) = 3jm + 4jm = 7jm
Distance between the two charges = √(0^2 + 7^2 + 0^2) = √49 = 7jm
The force between the two charges can be calculated using Coulomb's law:
F = k * (q1 * q2) / r^2
where k is the electrostatic constant (8.99 x 10^9 N m^2/C^2) and r is the distance between the charges.
F = (8.99 x 10^9) * (5 * 125 * 10^-9) / (7 * 10^-3)^2
F = (8.99 x 10^9) * (0.625) / 0.049
F = 1148244.9 N
Now, let's find the force between the 5C charge at 3jm and the 125nC charge at 4im:
Distance between the two charges = 3jm - 4im = 3jm - 4 * 10^-3 jm = 3jm - 4mmm = 3jm - 4mm = 3jm - 0.004mm
Distance between the two charges = √(0^2 + 3^2 + -0.004^2) = √(9 + 0.000016) = √9.000016 = 3.0000028jm
The force between the two charges can be calculated using Coulomb's law:
F = k * (q1 * q2) / r^2
where k is the electrostatic constant (8.99 x 10^9 N m^2/C^2) and r is the distance between the charges.
F = (8.99 x 10^9) * (5 * 125 * 10^-9) / (3.0000028 * 10^-3)^2
F = (8.99 x 10^9) * (0.625) / 9.0000028
F = 6244125.78185 N
Therefore, the electrostatic force due to the given point charge configuration is 1148244.9 N between the charges at 3jm and -4jm, and 6244125.78185 N between the charges at 3jm and 4im.