Two ships leave a harbor at the same time. One ship travels on a bearing s * 11 deg * w at 16 miles per hourThe other ship travels on a bearing N * 75 deg * E at 10 miles per hourHow far apart will the ships be after 3 hours? The distance is approximatelymiles(Round to the nearest tenth as needed.)
To find the distance between the two ships after 3 hours, we can calculate the distance each ship has traveled and then use the Pythagorean theorem to find the total distance between them.
Ship 1:
Speed = 16 miles per hour
Time = 3 hours
Distance = Speed * Time = 16 * 3 = 48 miles
Ship 2:
Speed = 10 miles per hour
Time = 3 hours
Distance = Speed * Time = 10 * 3 = 30 miles
Now, we can calculate the distance between the two ships using the Pythagorean theorem:
Distance^2 = 48^2 + 30^2
Distance^2 = 2304 + 900
Distance^2 = 3204
Distance ≈ √3204
Distance ≈ 56.6 miles
Therefore, the ships will be approximately 56.6 miles apart after 3 hours.