Calculate the mass of chlorine in a 198 L sample of the gas stored at 35°C and a pressure of 388 kPa.
To calculate the mass of chlorine in the sample, we need to use the ideal gas law equation:
PV = nRT
Where:
P = pressure (in Pa)
V = volume (in m^3)
n = number of moles
R = ideal gas constant (8.314 J/mol*K)
T = temperature (in K)
First, convert the given volume to cubic meters:
198 L = 0.198 m^3
Next, convert the temperature to Kelvin:
35°C = 35 + 273 = 308 K
Now, rearrange the ideal gas law equation to solve for the number of moles:
n = PV / RT
n = (388000 Pa * 0.198 m^3) / (8.314 J/mol*K * 308 K)
n = 1925.85 mol
Next, calculate the molar mass of chlorine, which is 35.45 g/mol.
Now, calculate the mass of chlorine in the sample:
mass = number of moles * molar mass
mass = 1925.85 mol * 35.45 g/mol
mass = 68293.9 g
Therefore, the mass of chlorine in the 198 L sample of gas stored at 35°C and a pressure of 388 kPa is 68,293.9 grams.