In a crash test, a 2,500 kg car hits a concrete barrier at 1.3 m/s2.
If the car strikes the barrier with a force of 3,250 N, how much resistance force does the barrier provide?
N
This pair of forces is an example of Newton’s
law of motion.
The resistance force provided by the barrier can be calculated using the equation:
Resistance Force = Force of car - Force from barrier
Resistance Force = 3,250 N
Therefore, the resistance force provided by the barrier is 3,250 N.
This pair of forces is an example of Newton's third law of motion, which states that for every action, there is an equal and opposite reaction. In this case, the force exerted by the car on the barrier is equal in magnitude but opposite in direction to the resistance force provided by the barrier.