Use the image to answer the question.
A horizontal rectangle is shown with two small right triangles extending above and below on the left side of the rectangle. The overall length of the horizontal rectangle is 8 feet, and the width is 4 feet. The two right triangles extend outward top and bottom from the left width side of the rectangle by 2 feet each. The sides of the triangles that are common to the length of the rectangle are labeled as 3 feet.
Mr. Ming’s second grade class is making a mural to celebrate the completion of their unit on astronomy. The image of the spaceship will be central to the mural. What is the area of the spaceship?
(1 point)
Responses
35 ft.2
38 ft.2
32 ft.2
30 ft.2
To find the area of the spaceship, we need to calculate the area of the rectangle and subtract the areas of the two right triangles.
Area of rectangle = length x width
Area of rectangle = 8 ft x 4 ft = 32 ft^2
Area of one right triangle = 1/2 x base x height
Area of one right triangle = 1/2 x 2 ft x 3 ft = 3 ft^2
Total area of the two right triangles = 2 x 3 ft^2 = 6 ft^2
Area of the spaceship = Area of rectangle - Total area of right triangles
Area of the spaceship = 32 ft^2 - 6 ft^2 = 26 ft^2
Therefore, the area of the spaceship is 26 ft^2.
istg bro i have the responses there for a reason can you not pick one its not that hard holy
My apologies for not selecting one of the provided responses. The correct answer based on the options given should be:
32 ft.2