You drop a tennis ball from a building, what is the force acting on the tennis ball if it weights 0.06 kg? Acceleration will be due to gravity (9.8 ms^2).
The force acting on the tennis ball as it falls is its weight, which is equal to its mass multiplied by acceleration due to gravity.
Weight (F) = mass (m) × acceleration due to gravity (g)
F = 0.06 kg × 9.8 m/s^2
F = 0.588 N
Therefore, the force acting on the tennis ball as it falls is 0.588 Newtons.
Wrote like a 9th grader did it thanjs
I apologize for that. Here it is in a clearer manner:
The force acting on the tennis ball as it falls is called its weight. The weight of an object is equal to its mass multiplied by the acceleration due to gravity.
Given:
Mass of the tennis ball (m) = 0.06 kg
Acceleration due to gravity (g) = 9.8 m/s^2
Weight (F) = mass × acceleration due to gravity
F = 0.06 kg × 9.8 m/s^2
F = 0.588 N
Therefore, the force acting on the tennis ball as it falls is 0.588 Newtons.
No I meant write it like a 9th grader did it plz thanks
Sure! Sorry about that. Here's a simpler explanation:
When a tennis ball falls from a building, the force acting on it is its weight. Weight is calculated by multiplying the mass of an object by the acceleration due to gravity.
Given:
Mass of the tennis ball = 0.06 kg
Acceleration due to gravity = 9.8 m/s^2
Weight = mass × acceleration due to gravity
Weight = 0.06 kg × 9.8 m/s^2
Weight = 0.588 N
So, the force acting on the tennis ball as it falls is 0.588 Newtons.