What is the percent by mass of C in methyl
acetate (C3H6O2)? The molecular weight
of carbon is 12.0107 g/mol, of hydrogen
1.00794 g/mol, and of oxygen 15.9994 g/mol.
Answer in units of %.
Please work it out for me so I totally understand it. Thanks!
1. figure the molecular mass of C3H6O2
Then, the percent of C
percent= 3*12.01/molmass * 100
To find the percent by mass of carbon (C) in methyl acetate (C3H6O2), we need to determine the mass of carbon in one mole of methyl acetate and then calculate its percentage.
First, we need to find the molar mass of methyl acetate (C3H6O2):
Molar mass of C = 12.0107 g/mol
Molar mass of H = 1.00794 g/mol
Molar mass of O = 15.9994 g/mol
Now, let's calculate the molar mass of methyl acetate:
Molar mass of methyl acetate (C3H6O2) = (3 * Molar mass of C) + (6 * Molar mass of H) + (2 * Molar mass of O)
= (3 * 12.0107 g/mol) + (6 * 1.00794 g/mol) + (2 * 15.9994 g/mol)
= 44.05274 g/mol
Next, we can calculate the mass of carbon in one mole of methyl acetate:
Mass of carbon = (number of moles of C) * (molar mass of C)
= (3 moles) * (12.0107 g/mol)
= 36.0321 g
Finally, we can determine the percent by mass of carbon in methyl acetate:
Percent by mass of C = (mass of carbon / mass of methyl acetate) * 100%
= (36.0321 g / 44.05274 g) * 100%
≈ 81.93%
Therefore, the percent by mass of carbon in methyl acetate (C3H6O2) is approximately 81.93%.
To find the percent by mass of carbon (C) in methyl acetate (C3H6O2), we need to calculate the mass of carbon in one mole of methyl acetate, and then divide it by the molar mass of methyl acetate, which includes the masses of carbon, hydrogen, and oxygen.
First, let's calculate the molar mass of methyl acetate (C3H6O2):
Molar mass of carbon (C) = 12.0107 g/mol
Molar mass of hydrogen (H) = 1.00794 g/mol
Molar mass of oxygen (O) = 15.9994 g/mol
Molar mass of methyl acetate (C3H6O2) = (3 * molar mass of carbon) + (6 * molar mass of hydrogen) + (2 * molar mass of oxygen)
= (3 * 12.0107 g/mol) + (6 * 1.00794 g/mol) + (2 * 15.9994 g/mol)
= 44.052 g/mol
Now, we need to find the mass of carbon in one mole of methyl acetate. Since there are three carbon atoms in one molecule of methyl acetate, we can calculate the mass of carbon as follows:
Mass of carbon = (3 * molar mass of carbon)
= 3 * 12.0107 g/mol
= 36.0321 g
Finally, to find the percent by mass of carbon in methyl acetate, we divide the mass of carbon by the molar mass of methyl acetate and multiply by 100:
Percent by mass of carbon = (Mass of carbon / Molar mass of methyl acetate) * 100
= (36.0321 g / 44.052 g/mol) * 100
≈ 81.83%
Therefore, the percent by mass of carbon in methyl acetate is approximately 81.83%.