Solve the system of two equations using substitution. y=2+3x and 4x-3y=-16
First, substitute y=2+3x into the second equation:
4x - 3(2 + 3x) = -16
4x - 6 - 9x = -16
-5x - 6 = -16
-5x = -10
x = 2
Now, substitute x=2 back into the first equation to find y:
y = 2 + 3(2)
y = 2 + 6
y = 8
Therefore, the solution to the system of equations is x=2 and y=8.