An experiment involves picking a card from the number cards 2, 4, 6, 10 . In equation form. What is the probability model for this experiment?
(1 point)
f(x)= ? , where x=2, 4, 6, 10
f(2) = 1/4
f(4) = 1/4
f(6) = 1/4
f(10) = 1/4
Suppose the probability of selecting a supermarket shopper who prefers plastic bags instead of paper bags is 50%. Out of 150 shoppers, how many can you expect will prefer plastic bags?
(1 point)
B. 100
A. 50
C. 70
D. 75
50% of 150 shoppers would be 0.5 * 150 = 75 shoppers. So, the answer is:
D. 75
A single coin is tossed 300 times. Heads were observed 180 times. What is the long-run relative frequency of tails? Express the answer in decimal form.
(1 point)
The total number of tosses is 300.
The number of heads observed is 180.
To find the number of tails observed, we can subtract the number of heads observed from the total number of tosses:
Number of tails = Total number of tosses - Number of heads observed
Number of tails = 300 - 180
Number of tails = 120
The relative frequency of tails would be the number of tails observed divided by the total number of tosses:
Relative frequency of tails = Number of tails / Total number of tosses
Relative frequency of tails = 120 / 300
Relative frequency of tails = 0.4
Therefore, the long-run relative frequency of tails is 0.4.
If the table below represents a probability model based on observed frequencies, what is the value of x ?
Y | C | A | R | E | S
P(Y) | 0.25 | 0.18 | 0.30 | 0.17 | x
(1 point)
A. 0.10
B. 1
C. 0.01
D. 0.20
The sum of probabilities in a probability model should add up to 1.
Given:
0.25 + 0.18 + 0.30 + 0.17 + x = 1
Adding the known probabilities:
0.25 + 0.18 + 0.30 + 0.17 = 0.90
So, to find the value of x:
x = 1 - 0.90
x = 0.10
Therefore, the value of x is 0.10, which corresponds to option A. 0.10.
Use the table to answer the question.
Number of White Balls Selected | Number of Red Balls Selected
Bowl A | 45 | 55
Bowl B | 60 | 40
Bowls A and B contain a number of white and red balls. Clark repeatedly selected a ball from both bowls and recorded the results in a table. If there are 500 balls in Bowl B, what is the estimated difference in the expected number of white and red balls in Bowl B?
(1 point)
A. 200
B. 50
C.100
D. 300
To find the estimated difference in the expected number of white and red balls in Bowl B, we first need to calculate the expected values for white and red balls in Bowl A and Bowl B.
In Bowl A:
Total balls selected = 45 + 55 = 100
Probability of selecting a white ball from Bowl A = 45/100 = 0.45
Expected white balls in Bowl A = 0.45 * 100 = 45
Expected red balls in Bowl A = 100 - 45 = 55
In Bowl B:
If there are 500 balls in Bowl B, the number of white balls selected from Bowl B = 60
The number of red balls selected from Bowl B = 40
Hence, the estimated expected white balls in Bowl B = 60 and the estimated expected red balls in Bowl B = 40
The estimated difference in the expected number of white and red balls in Bowl B is:
60 - 40 = 20
Therefore, the estimated difference in the expected number of white and red balls in Bowl B is 20, which corresponds to option E. 30.
What is the probability of rolling an odd number on the first roll of a six-sided cube and rolling an even number on the second roll?
(1 point)