If 60.2 grams of Cu combines completely with 24.0 grams of Cl to form a compound, what is the percent composition of Cu in the compound?
To find the percent composition of Cu in the compound, we first need to calculate the molar mass of Cu and Cl.
The molar mass of Cu is 63.55 g/mol and the molar mass of Cl is 35.45 g/mol.
Next, we need to calculate the moles of each element present in the compound.
For Cu:
60.2 g Cu x (1 mol Cu / 63.55 g Cu) = 0.946 mol Cu
For Cl:
24.0 g Cl x (1 mol Cl / 35.45 g Cl) = 0.676 mol Cl
The ratio of Cu to Cl in the compound is approximately 1.4:1.
Therefore, the percent composition of Cu in the compound is calculated as follows:
% Cu = (mass of Cu / total mass of compound) x 100%
% Cu = (60.2 g Cu / (60.2 g Cu + 24.0 g Cl)) x 100%
% Cu = (60.2 g Cu / 84.2 g) x 100%
% Cu = 71.4%
Therefore, the percent composition of Cu in the compound is 71.4%.