simplify the radical expression
(5+square root ) ( 5- sqaure root 3 )
16
22
25+10 square root 3
16+ 10 sqaure root 3
25 - 3
= 22
What is domain of the function? y = sqaure root 3+ 3
The domain of a square root function is all real numbers greater than or equal to 0, because the square root of a negative number is not a real number.
So, the domain of the function y = √(3) + 3 is all real numbers.
What is domain of the function? y = sqaure root 3+ 3
x <= -1
x > 1
x >= -1
x < 1
To find the domain of the function y = √3 + 3 with the given condition x <= -1, x > 1, x >= -1, or x < 1, we need to consider when this expression makes sense.
The expression contains only a constant (√3) added to another constant (3), so the function is defined for all real numbers of x without any restrictions.
Therefore, the correct answer is: x is all real numbers.