A drawer contains 5 red socks, 7 white socks, and 4 blue socks. Without looking, you draw out a sock and then draw out a second sock without returning the first sockWhat is the probability that the first sock and the second sock are both red?
To find the probability that both the first sock and the second sock drawn are red, we need to consider the total number of ways we can draw two socks out of the drawer and the number of ways we can draw two red socks.
Total number of ways to draw 2 socks out of 16 socks = 16C2 = (16*15) / (2*1) = 120
Number of ways to draw 2 red socks out of 5 red socks = 5C2 = (5*4) / (2*1) = 10
Therefore, the probability of drawing two red socks is:
P(two red socks) = Number of ways to draw 2 red socks / Total number of ways to draw 2 socks
P(two red socks) = 10 / 120
P(two red socks) = 1 / 12
So, the probability that the first sock and the second sock drawn are both red is 1/12.