There is a spinner with 9 equal areas, numbered 1 through 9. If the spinner is spun one time, what is the probability that the result is a multiple of 3 or a multiple of 2?
There are a total of 3 numbers that are multiples of 3 (3, 6, 9) and 4 numbers that are multiples of 2 (2, 4, 6, 8). However, the number 6 is both a multiple of 3 and 2.
Therefore, the probability of getting a multiple of 3 or a multiple of 2 is the sum of the individual probabilities minus the probability of getting 6 (to avoid double-counting):
P(3 or 2) = P(3) + P(2) - P(6) = 3/9 + 4/9 - 1/9 = 6/9 = 2/3
So, the probability of getting a multiple of 3 or a multiple of 2 on one spin of the spinner is 2/3.