Calculate the number of grams of solute in 500.0 mL of 0.169 M KOH
To calculate the number of grams of solute in 500.0 mL of 0.169 M KOH (potassium hydroxide), we need to use the formula:
moles = molarity (M) x volume (L)
First, we convert the volume from milliliters to liters:
500.0 mL = 500.0/1000 = 0.500 L
Now we can plug in the values and calculate the number of moles:
moles = 0.169 M x 0.500 L
moles = 0.0845 moles
Next, we need to calculate the molar mass of KOH:
K (potassium) = 39.10 g/mol
O (oxygen) = 16.00 g/mol
H (hydrogen) = 1.01 g/mol
Molar mass of KOH = 39.10 + 16.00 + 1.01 = 56.11 g/mol
Finally, we calculate the number of grams of KOH:
grams = moles x molar mass
grams = 0.0845 moles x 56.11 g/mol
grams = 4.746 g
Therefore, there are 4.746 grams of KOH in 500.0 mL of 0.169 M KOH solution.