How many grams of water react to form 4.50 moles of Sr(OH),?
SrO(s) + H2O(l)→ Sr(OH)2(s)
To determine how many grams of water react to form 4.50 moles of Sr(OH)2, we can use the stoichiometry of the reaction.
From the balanced chemical equation, we can see that 1 mole of SrO reacts with 1 mole of H2O to form 1 mole of Sr(OH)2.
This means that for every mole of Sr(OH)2 produced, 1 mole of water is consumed.
Therefore, for 4.50 moles of Sr(OH)2, 4.50 moles of water are consumed.
Now we can use the molar mass of water (H2O) to convert moles of water to grams:
Molar mass of H2O = 18.015 g/mol
4.50 moles H2O x 18.015 g/mol = 81.068 g of water
Therefore, 81.068 grams of water react to form 4.50 moles of Sr(OH)2.