Find the length of the diagonal AB: (5 points). You would first use ____ on the bottom of the box rectangle to find the diagonal CB = __ Then use CB as ____ of the triangle ABC, with AB being the____ . AB is approximately = ___
You would first use the Pythagorean theorem on the bottom of the box rectangle to find the diagonal CB = sqrt(10^2 + 6^2) = sqrt(100 + 36) = sqrt(136).
Then use CB as the hypotenuse of the triangle ABC, with AB being the other side. So, AB = sqrt(CB^2 + 4^2) = sqrt(136 + 16) = sqrt(152).
Therefore, AB is approximately equal to sqrt(152), which is approximately 12.33 units.