How many mL of HCI, 0.1 M. will you need to prepare 0.700 L of HCL, 0.025 M?
To calculate this, we can use the formula:
M1V1 = M2V2
Where:
M1 = initial molarity of the HCl solution
V1 = initial volume of the HCl solution
M2 = final molarity of the HCl solution
V2 = final volume of the HCl solution
Given:
M1 = 0.1 M
M2 = 0.025 M
V2 = 0.700 L
We can substitute these values into the formula to find V1:
(0.1 M)(V1) = (0.025 M)(0.700 L)
V1 = (0.025 M)(0.700 L) / 0.1 M
V1 = 0.175 L
Therefore, you will need 0.175 L or 175 mL of 0.1 M HCl solution to prepare 0.700 L of 0.025 M HCl solution.