Calculate the molarity of a solution prepared by the addition of 2.59 g of NaNO3 into 250. mL of solution.
To calculate the molarity of the solution, we first need to determine the number of moles of NaNO3 that were added to the solution.
Step 1: Calculate the molar mass of NaNO3
Na - 22.99 g/mol
N - 14.01 g/mol
O - 16.00 g/mol
Molar mass of NaNO3 = 22.99 + 14.01 + (3 * 16.00) = 85.00 g/mol
Step 2: Calculate the number of moles of NaNO3 added
Number of moles = Mass / Molar mass
Number of moles = 2.59 g / 85.00 g/mol = 0.03047 mol
Step 3: Calculate the volume of the solution in liters
Volume of solution = 250. mL / 1000 = 0.250 L
Step 4: Calculate the molarity of the solution
Molarity = Number of moles / Volume of solution
Molarity = 0.03047 mol / 0.250 L = 0.122 M
Therefore, the molarity of the solution prepared by adding 2.59 g of NaNO3 into 250. mL of solution is 0.122 M.