Calculate the volume in L in a 1.5 M NaHCO3, solution that contains 12.7 g of NaHCO3.
To calculate the volume of the solution, we first need to convert the mass of NaHCO3 to moles using its molar mass.
Molar mass of NaHCO3:
Na: 22.99 g/mol
H: 1.01 g/mol
C: 12.01 g/mol
O: 16.00 g/mol
NaHCO3 = 22.99 + 1.01 + 12.01 + (3 x 16.00)
NaHCO3 = 22.99 + 1.01 + 12.01 + 48.00
NaHCO3 = 84.01 g/mol
Next, calculate the number of moles in 12.7 g of NaHCO3:
12.7 g / 84.01 g/mol = 0.151 mol
Now, use the molarity formula to find the volume of the solution:
Molarity = moles / volume
1.5 M = 0.151 mol / volume
Volume = 0.151 mol / 1.5 M
Volume = 0.1007 L or 100.7 mL
Therefore, the volume of a 1.5 M NaHCO3 solution containing 12.7 g of NaHCO3 is 100.7 mL.