what's the distance between (19, -6) and (8, -6) on a coordinate plane?
The distance between two points on a coordinate plane can be calculated using the distance formula:
√((x2 - x1)^2 + (y2 - y1)^2)
Plugging in the coordinates (19, -6) and (8, -6) into the formula:
√((8 - 19)^2 + (-6 - (-6))^2)
= √((-11)^2 + (0)^2)
= √(121)
= 11
Therefore, the distance between the points (19, -6) and (8, -6) on a coordinate plane is 11 units.