What is the area of a regular pentagon with a side of 12 in.? Round the answer to the nearest tenth.
To find the area of a regular pentagon, you can use the formula:
Area = 1/4 * √(5(5 + 2√5)) * s^2
Where s is the length of one side of the pentagon.
Substitute s = 12 in:
Area = 1/4 * √(5(5 + 2√5)) * 12^2
Area = 1/4 * √(5(5 + 2√5)) * 144
Area = 1/4 * √(5(5 + 2√5)) * 144
Area = 1/4 * √(5(5 + 2√5)) * 144
Area ≈ 690.1 in^2
Therefore, the area of a regular pentagon with a side length of 12 in. is approximately 690.1 square inches.