An elliptical track has a major axis that is 80 yards long and a minor axis that is 72 yards long. Find an equation for the track if its center is (0, 0) and the major axis is the x-axis.
The equation of an ellipse with center at the origin and major axis along the x-axis is given by:
$\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$
where $a$ is the length of the semi-major axis and $b$ is the length of the semi-minor axis.
In this case, the length of the major axis is 80 yards, so $a = 40$ yards and the length of the minor axis is 72 yards, so $b = 36$ yards.
Therefore, the equation of the elliptical track is:
$\frac{x^2}{40^2} + \frac{y^2}{36^2} = 1$
Simplifying, we get:
$ \frac{x^2}{1600} + \frac{y^2}{1296} = 1$