Suppose you are a solving a quadratic equation using the quadratic formula and this is your work so far: 3x^2+4x-1=0
It seems like you have correctly identified the quadratic equation you are trying to solve: 3x^2 + 4x - 1 = 0. Now you can use the quadratic formula to find the solutions for this equation.
The quadratic formula is x = (-b ± √(b^2 - 4ac)) / 2a, where a, b, and c are the coefficients of the quadratic equation ax^2 + bx + c = 0.
In your case, a = 3, b = 4, and c = -1. Plugging these values into the formula, you would get:
x = (-4 ± √(4^2 - 4*3*(-1))) / 2*3
x = (-4 ± √(16 + 12)) / 6
x = (-4 ± √28) / 6
x = (-4 ± 2√7) / 6
So, the solutions to the quadratic equation 3x^2 + 4x - 1 = 0 are:
x = (-4 + 2√7) / 6
x = (-4 - 2√7) / 6
Therefore, the correct solutions to the quadratic equation are x = (-4 + 2√7) / 6 and x = (-4 - 2√7) / 6.