Suppose that the functions r and s are defined for all real numbers x as follows.
r（2） =3x-2
s（x）=x+2
Write the expressions for (r+s) (x) and (r-s) (x) and evaluate (r-s) (3).
(r*s)(x) =
To find the expressions for (r+s)(x) and (r-s)(x), we simply add or subtract the given functions r and s.
(r+s)(x) = r(x) + s(x) = (3x-2) + (x+2) = 4x
(r-s)(x) = r(x) - s(x) = (3x-2) - (x+2) = 2x - 4
To evaluate (r-s)(3), we plug in x=3 into the expression we found:
(r-s)(3) = 2(3) - 4 = 6 - 4 = 2
Therefore, (r-s)(3) = 2.