A teacher wants to make 200 ml of a 0.600 mol/L solution of KOH(aq). What volume of a 2.00-mol/L stock solution is required for this dilution
To make a 0.600 mol/L solution of KOH(aq) with a final volume of 200 ml, we can use the formula for dilution:
M1V1 = M2V2
M1 = initial molarity = 2.00 mol/L (stock solution)
V1 = initial volume = unknown
M2 = final molarity = 0.600 mol/L
V2 = final volume = 200 ml = 0.200 L
Plugging in the values:
(2.00 mol/L)V1 = (0.600 mol/L)(0.200 L)
V1 = (0.600 mol/L)(0.200 L) / 2.00 mol/L
V1 = 0.060 L
Therefore, the teacher needs to use 0.060 L or 60 ml of the 2.00-mol/L stock solution to make 200 ml of a 0.600 mol/L solution of KOH(aq) after dilution.