In a binomial experiment with and . Find
0.0982
0.0409
0.0648
0.1228
0.1564
To find the probability of exactly 1 success in a binomial experiment with n = 3 and p = 0.6, we can use the binomial probability formula:
P(X=k) = (n choose k) * p^k * (1-p)^(n-k)
where n is the number of trials, p is the probability of success, k is the number of successes, and (n choose k) is the number of ways to choose k successes out of n trials.
Plugging in the values n = 3, p = 0.6, and k = 1:
P(X=1) = (3 choose 1) * 0.6^1 * (1-0.6)^(3-1)
P(X=1) = 3 * 0.6 * 0.4^2
P(X=1) = 3 * 0.6 * 0.16
P(X=1) = 0.288
Therefore, the probability of exactly 1 success in a binomial experiment with n = 3 and p = 0.6 is 0.288. None of the options provided match this value.