Martha has a soup can in the shape of a cylinder with a height of 11 cm and radius of 4 cm. What is the surface area of the can? Use 3.14 for π and round to the nearest tenth
the answer is not 376
To find the surface area of the soup can, we need to find the area of the two circles that make up the top and bottom of the cylinder, as well as the area of the side of the cylinder.
1. Area of the top circle: A = πr^2
A = 3.14 * 4^2
A = 3.14 * 16
A = 50.24 square cm
2. Area of the bottom circle: (same as top circle)
A = 50.24 square cm
3. Area of the side of the cylinder: A = 2πrh
A = 2 * 3.14 * 4 * 11
A = 8 * 3.14 * 11
A = 87.92 square cm
Now, add up the areas of the two circles and the side of the cylinder to get the total surface area:
50.24 + 50.24 + 87.92 = 188.4 square cm
Therefore, the surface area of the soup can is 188.4 square cm (rounded to the nearest tenth).
nope not 188.4 either
I apologize. Let's try calculating it again:
Surface Area of the Cylinder = 2πr(r + h)
Given:
- Radius (r) = 4 cm
- Height (h) = 11 cm
Plugging in these values:
Surface Area = 2 * 3.14 * 4(4 + 11)
Surface Area = 2 * 3.14 * 4 * 15
Surface Area = 25.12 * 15
Surface Area = 376.8 square cm
Therefore, the surface area of the soup can is 376.8 square cm (rounded to the nearest tenth).
nope
I apologize for the error. Let's calculate the surface area of the cylinder again:
The surface area of a cylinder is given by the formula:
Surface Area = 2πr(r + h)
Given:
- Radius (r) = 4 cm
- Height (h) = 11 cm
Plugging in these values:
Surface Area = 2 * 3.14 * 4(4 + 11)
Surface Area = 2 * 3.14 * 4 * 15
Surface Area = 2 * 3.14 * 60
Surface Area = 376.8 cm^2
Therefore, the surface area of the soup can is approximately 376.8 square cm.