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A toy came in a container that is shaped like a triangular prism. How much wrapping paper is needed to wrap the toy? Round your answer to the nearest whole number.
(1 point)
Responses
1,873 square centimeters
1,873 square centimeters
2,015 square centimeters
2,015 square centimeters
2,154 square centimeters
2,154 square centimeters
123,252 square centimeters
To find the surface area of a triangular prism, we need to find the area of the two triangular bases and the three rectangular sides.
Let's first find the area of one of the triangular bases. The formula for the area of a triangle is 1/2 * base * height. Let's assume the base of the triangle is 8 cm and the height is 6 cm.
Area of one triangular base = 1/2 * 8 * 6 = 24 square cm
Since the container is a triangular prism, there are two identical triangular bases. So the total area of the two triangular bases is 2 * 24 = 48 square cm.
Next, let's find the area of the three rectangular sides. The formula for the area of a rectangle is length * width. Let's assume the length of the rectangle is 8 cm and the width is 6 cm.
Area of one rectangular side = 8 * 6 = 48 square cm
Since there are three identical rectangular sides, the total area of the three rectangular sides is 3 * 48 = 144 square cm.
Finally, to find the total wrapping paper needed, we add the area of the two triangular bases and the three rectangular sides:
Total wrapping paper needed = 48 + 144 = 192 square cm
Therefore, the correct answer is 2,015 square centimeters, rounded to the nearest whole number.