The radius of the given circle is 6 cm and 0=60% , that is, pi/3
The area of shaded region needs to be found.
Answers: (Pick 1)
(120π+253–√)m2 open paren 120 pi plus 25 square root of 3 close paren times m squared (30π+53–√)m2 open paren 30 pi plus 5 square root of 3 close paren times m squared (96π+253–√)m2 open paren 96 pi plus 25 square root of 3 close paren times m squared (30π+93–√)m2
The area of the shaded region can be found by first calculating the area of the entire circle and then subtracting the area of the sector determined by the central angle of 60 degrees.
Area of circle = πr^2 = π(6)^2 = 36π
Area of sector = (60/360) x πr^2 = (1/6) x 36π = 6π
Therefore, the area of the shaded region = 36π - 6π = 30π
So, the correct answer would be:
(30π+5√3)m2 (30 pi plus 5 times square root of 3) square meters