What is the area of a regular pentagon with a side of 12in? Round the answer to the nearest tenth. (1 point) Responses 192.6 192.6 247.7 247.7 172.0 172.0 344.1
The formula to find the area of a regular pentagon is A = (1/4) * √(5(5 + 2√5)) * s^2, where s is the length of a side.
Using the formula and plugging in s = 12in, we get:
A = (1/4) * √(5(5 + 2√5)) * 12^2
A = (1/4) * √(5(5 + 2√5)) * 144
A = (1/4) * √(5(5 + 2√5)) * 144
A = (1/4) * √(5(5 + 2√5)) * 144
A = (1/4) * √(5(5 + 2√5)) * 144
A = (1/4) * √(5(5 + 2√5)) * 144
A ≈ 247.7
Therefore, the area of the regular pentagon with a side of 12in is approximately 247.7 square inches. The answer is:
247.7