Your employer is offering free tickets for two baseball games. They play
56
56 home games and
8
8 of them are against the Snakes. The tickets are randomly given out. What is the probability that both are games are against the Snakes? Write your answer as a fraction. You do not need to simplify.
To find the probability that both tickets are for games against the Snakes, we need to calculate the probability of getting a game against the Snakes for the first ticket and then multiply it by the probability of getting a game against the Snakes for the second ticket.
The total number of possible outcomes is the total number of games, which is 56.
The probability of getting a game against the Snakes for the first ticket is 8 out of 56, which can be written as 8/56.
Since the first ticket has already been given out, there are now only 55 games left, and 7 games against the Snakes left. So, the probability of getting a game against the Snakes for the second ticket is 7/55.
Therefore, the probability that both tickets are for games against the Snakes is:
(8/56) * (7/55) = 56/3080 = 56/3080.
So, the probability that both games are against the Snakes is 56/3080.