(-2, 1)
(4,3)
Put the steps in order to find the distance between these 2 points.
Step 1
Step 2
Step 3
Step 4
Step 5
Step 6
Step 7
1. ::Use the Pythagorean Theorem for right triangles to
determine the diagonal length: 22 +6² = c²
2. :: 40 = c²
3. ::Draw a right triangle by dropping a vertical side and a
horizontal side.
4. :: √40=√c²
5. ::40 is between √36 and 149, so between 6 and 7 -
closer to 6, so about 6.3 units
6. ::Determine the vertical side (2 units) and horizontal side
(6 units) lengths by counting on the grid (be careful of
the scale), or using the vertical coordinates (3 to 1) and
horizontal coordinates (-2 to 4).
7. ::= 4+36= c²
Note: There seems to be a mistake in Step 7, as 4 + 36 does not equal c². The correct formula to use for Step 7 would be 4² + 36² = c².
(-2, 1) to (4,3)
delta x = 4 - -2 = 6
delta y = 3 - 1 = 2
sqrt (6^2 + 2^2 = sqrt(36+4) = sqrt 40 = sqrt (4*10) = 2 s
To find the distance between the points (-2, 1) and (4, 3), you can use the distance formula:
√((x₂ - x₁)² + (y₂ - y₁)²)
Plugging in the values:
√((4 - (-2))² + (3 - 1)²)
√((4 + 2)² + (3 - 1)²)
√(6² + 2²)
√(36 + 4)
√40
2√10
Therefore, the distance between the two points is 2√10 units.