Nan’s suitcase is on a bench. The suitcase has a mass of 14
kilograms. Nan accidentally knocks the suitcase off the bench, and the
suitcase falls at a speed of 2.7 meters per second. How much kinetic
energy does the suitcase have just before it hits the floor?
(1 point)
KE =
1
2mv
2
51.03 J
102.06 J
18.9 J
204.12 J
To calculate the kinetic energy of the suitcase just before it hits the floor, we can use the formula for kinetic energy:
KE = 1/2 * m * v^2
Where:
KE = kinetic energy
m = mass of the suitcase (14 kg)
v = speed of the suitcase (2.7 m/s)
Plugging in the values:
KE = 1/2 * 14 kg * (2.7 m/s)^2
KE = 1/2 * 14 kg * 7.29 m^2/s^2
KE = 7 * 7.29 J
KE = 51.03 J
Therefore, the kinetic energy of the suitcase just before it hits the floor is 51.03 Joules.
The correct answer is: KE = 51.03 J