The mean of each dataset that follows is 10. Which dataset is more spread out? Justify your answer using the mean absolute deviation of each dataset. Round your answers to the nearest tenth.
Dataset #1: {5,8,9,10,12,12,14}
Dataset #2: {5,6,8,9,10,10,22}
(2 points)
Dataset # ____ is more spread out because it has a mean absolute deviation of
a ______ while Dataset # ____ has a mean absolute deviation of a _____.
Dataset #2 is more spread out because it has a mean absolute deviation of 5.0 while Dataset #1 has a mean absolute deviation of 2.9.
wrong
I apologize for the mistake. Let's calculate the mean absolute deviation for each dataset:
Dataset #1:
Mean = 10
|5-10| + |8-10| + |9-10| + |10-10| + |12-10| + |12-10| + |14-10| = 5 + 2 + 1 + 0 + 2 + 2 + 4 = 16
Mean Absolute Deviation = 16/7 = 2.3
Dataset #2:
Mean = 10
|5-10| + |6-10| + |8-10| + |9-10| + |10-10| + |10-10| + |22-10| = 5 + 4 + 2 + 1 + 0 + 0 + 12 = 24
Mean Absolute Deviation = 24/7 = 3.4
Therefore, Dataset #1 is more spread out because it has a mean absolute deviation of 2.3 while Dataset #2 has a mean absolute deviation of 3.4.
still wrong
Apologies for the errors in my previous responses. Let's recalculate the mean absolute deviation for each dataset:
Dataset #1:
Mean = 10
|5-10| + |8-10| + |9-10| + |10-10| + |12-10| + |12-10| + |14-10| = 5 + 2 + 1 + 0 + 2 + 2 + 4 = 16
Mean Absolute Deviation = 16/7 = 2.3
Dataset #2:
Mean = 10
|5-10| + |6-10| + |8-10| + |9-10| + |10-10| + |10-10| + |22-10| = 5 + 4 + 2 + 1 + 0 + 0 + 12 = 24
Mean Absolute Deviation = 24/7 = 3.4
Therefore, Dataset #2 is more spread out because it has a mean absolute deviation of 3.4 while Dataset #1 has a mean absolute deviation of 2.3. Thank you for your patience.