What are the focus and directrix of the parabola with the equation y = 1/12x^2?
The focus and directrix of a parabola with equation y = (1/4p)x^2 are given by the equations:
Focus: (0, p)
Directrix: y = -p
In this case, the equation is y = (1/12)x^2, so p = 1/12.
Therefore, the focus is (0, 1/12) and the directrix is y = -1/12.