A survey of 80 employees was conducted asking about which meals they regularly eat at the office. twenty employees eat breakfast at the office, 50 eat lunch, and 15 eat both breakfast and lunch. if an employee is randomly selecting an employee who eat breakfast or lunch at the office?
the answer is 7/8
the again, the group of both only had 15 compared to the other ones. so you might be right with the answer before...
but why do you subtract the 15?
could you anwser this again? your wrong bot
Isn't the answer 11/16?
To find the probability that a randomly selected employee eats breakfast or lunch at the office, we need to calculate the total number of employees who eat breakfast, lunch, or both.
Total number of employees who eat breakfast = 20
Total number of employees who eat lunch = 50
Total number of employees who eat both breakfast and lunch = 15
Total number of employees who eat breakfast, lunch, or both = 20 + 50 - 15 = 55
Therefore, the probability that a randomly selected employee eats breakfast or lunch at the office is 55/80 or 0.6875.