The baynard high school boosters are selling hot dogs and pretzels at the concession stand. They have 300 hotdogs and pretzels in stock and want to earn an income of $800. They plan to sell the hotdogs for $4 each and the pretzels for $2 each. How many hotdogs and how many pretzels do the boosters need to sale to reach their goal $800
Let x be the number of hotdogs sold and y be the number of pretzels sold.
The total income from selling hotdogs is 4x and from selling pretzels is 2y. Since the goal is to earn $800, we can write the equation:
4x + 2y = 800
Also, the total number of items sold is 300, so we have:
x + y = 300
Now we have a system of two equations:
4x + 2y = 800
x + y = 300
Solving these equations simultaneously, we can find the values of x and y:
From the second equation, we get:
y = 300 - x
Substitute this into the first equation:
4x + 2(300 - x) = 800
4x + 600 - 2x = 800
2x + 600 = 800
2x = 200
x = 100
Now we can find the number of pretzels sold:
y = 300 - x
y = 300 - 100
y = 200
Therefore, the boosters need to sell 100 hotdogs and 200 pretzels to reach their goal of $800.