If the surface area of the net diagram of the right circular cylinder is 395.64 feet2 , find the height of the net diagram. Use 3.14 for π .
Radius of both circles = 3
The net diagram of the right circular cylinder consists of two circles (top and bottom) and a rectangle (the side).
The formula for the surface area of a cylinder is given by:
Surface Area = 2πr^2 + 2πrh
where r is the radius of the base, h is the height, and π is the constant pi.
Given that the radius of the circles is 3 ft, we have:
Surface Area = 2π(3)^2 + 2π(3)h
Surface Area = 18π + 6πh
Surface Area = 24π + 6πh
Given that the surface area is 395.64 ft^2, we can substitute this into the equation and solve for h:
395.64 = 24π + 6πh
395.64 = 24(3.14) + 6(3.14)h
395.64 = 75.36 + 18.84h
18.84h = 320.28
h = 320.28 / 18.84
h = 16.99
Therefore, the height of the net diagram of the right circular cylinder is approximately 16.99 feet.