You are tasked to graphing the equation y=413x+5 [Click Here for Help Video](10 points) The initial point (or y-intercept) is the point (, ) To plot the 2nd point we start at our initial point then use the slope to travel up 4 spaces, and right 13 spaces. This plots the 2nd point (, )
To graph the equation y=413x+5:
1. Identify the initial point (y-intercept): This occurs when x=0
y = 413(0) + 5
y = 5
So the initial point is (0, 5)
2. Use the slope to find the second point:
The slope of the equation is 413, which means for every 1 unit increase in x, y will increase by 413 units.
Starting from the initial point (0, 5), go up 4 units (413*1) and then right 13 units.
This gives us the second point:
x = 13
y = 413(13) + 5
= 5354
So the second point is (13, 5354)
Now plot these two points on the graph and draw a line through them to represent the equation y=413x+5.
You are tasked to graphing the equation y=413x+5 [Click Here for Help Video](10 points) The initial point (or y-intercept) is the point (, ) To plot the 2nd point we start at our initial point then use the slope to travel up 4 spaces, and right 13 spaces. This plots the 2nd point ( , )
To graph the equation y = 413x + 5, follow these steps to find the initial point and plot the second point:
1. Initial point (y-intercept):
When x = 0,
y = 413(0) + 5
y = 5
Therefore, the initial point is (0, 5).
2. Plotting the second point:
Use the slope of 413 to move up 4 units and right 1 unit to find the next point.
From the initial point (0, 5), go up 4 units and right 1 unit:
Second point:
x = 1
y = 413(1) + 5
y = 413 + 5
y = 418
So, the second point is (1, 418).
Now you have the initial point at (0, 5) and the second point at (1, 418). Plot these two points on the graph and draw a line through them to represent the equation y = 413x + 5.
paces. This plots the 2nd point
To plot the second point when graphing the equation y = 413x + 5, you can follow these steps:
1. Start with the initial point (y-intercept) which is at (0, 5).
When x = 0,
y = 413(0) + 5
y = 5
So, the initial point is (0, 5).
2. Use the slope to find the second point:
The slope of the equation is 413, which means for every 1 unit increase in x, y will increase by 413 units.
From the initial point (0, 5), move up 413 units (413*1) and then move right 1 unit to find the second point.
Second point:
x = 1
y = 413(1) + 5
= 413 + 5
= 418
So, the second point is (1, 418).
Now you can plot the initial point at (0, 5) and the second point at (1, 418) on the graph. Draw a line through these two points to represent the equation y = 413x + 5.