question-A standard deck of 52 cards contains four suits: hearts, diamonds, clubs, and spades. Each suit has 13 cards: ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, and king. Two cards are randomly drawn without replacement. Calculate the probability of drawing two diamond cards. Express your answer in percent form rounding to the nearest hundredth.
There are 13 diamond cards out of a total of 52 cards in the deck.
The probability of drawing a diamond card on the first draw is 13/52.
After drawing one diamond card, there are now 12 diamond cards left out of 51 total cards in the deck.
The probability of drawing a second diamond card is 12/51.
To find the probability of drawing two diamond cards, we multiply the probability of the first draw by the probability of the second draw:
(13/52) * (12/51) = 0.0588
Converting this probability to a percentage and rounding to the nearest hundredth gives us:
0.0588 * 100 = 5.88%
Therefore, the probability of drawing two diamond cards from a standard deck of 52 cards is 5.88%.
wrong
Let's correct the calculation:
The probability of drawing a diamond card on the first draw is 13/52.
After drawing one diamond card, there are now 12 diamond cards left out of 51 total cards in the deck.
The probability of drawing a second diamond card is 12/51.
To find the probability of drawing two diamond cards, we multiply the probability of the first draw by the probability of the second draw:
(13/52) * (12/51) = 0.0588
Converting this probability to a percentage and rounding to the nearest hundredth gives us:
0.0588 * 100 = 5.88%
Therefore, the probability of drawing two diamond cards from a standard deck of 52 cards is 5.88%.