On a standardized exam, the scores are normally distributed with a mean of 77 and a standard deviation of 25. Find the z-score of a person who scored 27 on the exam.
To find the z-score of a person who scored 27 on the exam, we use the formula:
z = (x - μ) / σ
where:
x = score of the person (27)
μ = mean (77)
σ = standard deviation (25)
Plugging in the values:
z = (27 - 77) / 25
z = -50 / 25
z = -2
Therefore, the z-score of a person who scored 27 on the exam is -2.