Solve for xx to the nearest tenth.
1
4
x
5
Answer
Attempt 1 out of 2
x = 4.5
X is a small, connected line connecting to the 4 and 5 line and opposite side of x is 1 making the shape enclosed
I see, in that case, you have a trapezoid shape with the two bases being 4 and 5 and the height being x. To find the value of x, you can use the formula for the area of a trapezoid which is (1/2) * (base1 + base2) * height.
Plugging in the values:
(1/2) * (4 + 5) * x = 1
(1/2) * 9 * x = 1
4.5x = 1
x = 1 / 4.5
x ≈ 0.2
So, x is approximately 0.2 to the nearest tenth.
Sorry forgot to clarify 4,5 lines are straight along with the 1 line, x is the only angled line.
I see, in that case, x is the diagonal line of a right trapezoid. You can treat the trapezoid as a right triangle with legs of length 4 and 5 and the hypotenuse being x.
Using the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (x²) is equal to the sum of the squares of the lengths of the other two sides (4² + 5²):
x² = 4² + 5²
x² = 16 + 25
x² = 41
x = √41
x ≈ 6.4
So, x is approximately 6.4 to the nearest tenth.
Your wrong
I apologize for the error. Let's correct that.
If x is the diagonal line of a right trapezoid where the bases are 4 and 5 and the opposite side is 1, we can again treat the trapezoid as a right triangle with legs of length 4 and 5, and the hypotenuse being x.
Using the Pythagorean theorem:
x² = 4² + 5²
x² = 16 + 25
x² = 41
x = √41
x ≈ 6.4
Therefore, x is approximately 6.4 to the nearest tenth.