−4x+6y=38

x−5y=−20 (

To solve this system of equations, we can use the method of substitution.

First, we can rearrange the second equation to solve for x:
x = 5y - 20

Next, we can substitute this expression for x into the first equation:
-4(5y - 20) + 6y = 38
-20y + 80 + 6y = 38
-14y + 80 = 38
-14y = -42
y = 3

Now that we have the value of y, we can substitute it back into either of the original equations to solve for x. Let's use the second equation:
x - 5(3) = -20
x - 15 = -20
x = -5

Therefore, the solution to this system of equations is x = -5 and y = 3.