Use the chemical equation to answer the question. 2HCl(ag) + Zn(s) → ZnCl2(aq) + H2(g) The molar mass of hydrogen (H) is 1g/mol, the molar mass of chlorine (Cl) is 35g/mol, and the molar mass of zinc (Zn) is 65g/mol. When 130g of zinc react completely in hydrochloric acid (HCl), how much is the total mass of the products? (1 point) Responses 274g 274g 270g 270g 144g 144g 130g 130g Skip to navigation
To find the total mass of the products, we first need to calculate the molar mass of zinc (ZnCl2) and hydrogen gas (H2) produced in the reaction.
The molar mass of ZnCl2 is 65g/mol (Zn) + 2(35g/mol) = 135g/mol
The molar mass of H2 is 2(1g/mol) = 2g/mol
Now, we need to find the moles of zinc (Zn) reacting:
130g Zn / 65g/mol = 2 moles Zn
From the balanced chemical equation, we see that 1 mole of Zn produces 1 mole of ZnCl2 and 1 mole of H2. Therefore, 2 moles of Zn will produce 2 moles of ZnCl2 and 2 moles of H2.
Now, calculate the total mass of the products:
2 moles ZnCl2 x 135g/mol = 270g ZnCl2 (aqueous)
2 moles H2 x 2g/mol = 4g H2 (gaseous)
Total mass of products = 270g ZnCl2 + 4g H2 = 274g
Therefore, the total mass of the products formed when 130g of zinc reacts completely in hydrochloric acid is 274g.