The cannon on a pirate ship shoots with a speed of 350 m/s (the muzzle velocity). The cannon can be adjusted to shoot at any elevation above the horizontal. If the cannon's barrel is 2 m long and the force on the ball is constant, and the acceleration if the ball in m/s^2 inside the barrel is 30,625, and the cannon ball mass is 5 kg, then what is the force on the cannon ball in N?
To calculate the force on the cannonball, we first need to calculate the acceleration of the cannonball in the barrel using the formula:
a = (Vf^2 - Vo^2) / (2 * d)
where:
a = acceleration (30,625 m/s^2)
Vo = initial velocity (0 m/s)
Vf = final velocity (350 m/s)
d = distance (2 m)
Now, we can calculate the force using Newton's second law of motion:
F = m * a
where:
F = force
m = mass (5 kg)
a = acceleration
Plugging in the values, we get:
F = 5 kg * 30,625 m/s^2
F = 153,125 N
Therefore, the force on the cannonball is 153,125 N.