A bag contains four red balls, three blue balls and two green balls. If one ball is drawn at random what is the probability of drawing a green or red ball?
There are a total of 9 balls in the bag, out of which 4 are red and 2 are green.
The probability of drawing a green or red ball = (Number of favorable outcomes) / (Total number of outcomes)
= (4 red balls + 2 green balls) / 9 total balls
= 6 / 9
= 2 / 3
Therefore, the probability of drawing a green or red ball is 2/3 or approximately 0.67.