Olga is making presents for her teachers and needs to wrap them. She places the gifts in a right circular cylinder with a height of 12 inches and diameter of 6 inches. How much wrapping paper does she need for each gift she is going to wrap? Use 3.14 for π .(1 point)
inches^2
First, we need to calculate the surface area of the cylinder to determine how much wrapping paper Olga will need.
The formula for the surface area of a cylinder is:
Surface Area = 2πr(r+h)
Given that the diameter is 6 inches, the radius (r) would be half of that, so r = 6/2 = 3 inches.
Now we can plug in the values:
Surface Area = 2 * 3.14 * 3(3 + 12)
Surface Area = 2 * 3.14 * 3(15)
Surface Area = 2 * 3.14 * 45
Surface Area = 282.6 inches^2
Therefore, Olga will need 282.6 square inches of wrapping paper for each gift she wraps.
UMM
I'll make the correction. The formula for the surface area of a cylinder is:
Surface Area = 2πr(r+h) + 2πr^2
Given that the diameter is 6 inches, the radius (r) would be half of that, so r = 6/2 = 3 inches.
Now we can plug in the values:
Surface Area = 2 * 3.14 * 3(3 + 12) + 2 * 3.14 * 3^2
Surface Area = 2 * 3.14 * 3(15) + 2 * 3.14 * 9
Surface Area = 2 * 3.14 * 45 + 2 * 3.14 * 9
Surface Area = 282.6 + 56.52
Surface Area = 339.12 inches^2
Therefore, Olga will need 339.12 square inches of wrapping paper for each gift she wraps.