Saya has a swimming pool in the shape of a rectangle. It is 16 1/2 ft. long, 8 1/4 ft. wide, and 3 1/2 ft. deep. How much water can the pool hold? Your answer should be a mixed number in simplest form.
To find the volume of the swimming pool, we multiply the length, width, and depth of the pool.
Volume = Length x Width x Depth
Volume = 16 1/2 ft. x 8 1/4 ft. x 3 1/2 ft.
Volume = (33/2) ft. x (33/4) ft. x (7/2) ft.
Volume = (33*33*7)/(2*4*2) ft.^3
Volume = 31.455 ft.^3
Therefore, the swimming pool can hold 31 5/11 ft.^3 of water.
wrong
I apologize for the mistake. Let me recalculate the volume of the swimming pool correctly:
Volume = Length x Width x Depth
Convert mixed numbers to improper fractions:
Length = 16 1/2 ft = 33/2 ft
Width = 8 1/4 ft = 33/4 ft
Depth = 3 1/2 ft = 7/2 ft
Volume = (33/2) ft x (33/4) ft x (7/2) ft
Volume = (33 x 33 x 7)/(2 x 4 x 2) ft^3
Volume = 31,185/(16) ft^3
Volume = 1,949.06 ft^3
Therefore, the swimming pool can hold 1,949 6/15 ft^3 of water. Simplifying to the simplest form:
1,949 6/15 ft^3 = 1,949 2/5 ft^3
So, the correct answer is that the swimming pool can hold 1,949 2/5 ft^3 of water. Thank you for your patience.
wronngggg
My apologies for the errors in the previous calculations. Let's correct it step by step:
1. Convert all mixed numbers to improper fractions:
- Length = 16 1/2 ft = 33/2 ft
- Width = 8 1/4 ft = 33/4 ft
- Depth = 3 1/2 ft = 7/2 ft
2. Calculate the volume of the pool using the formula: Volume = Length x Width x Depth
Volume = (33/2) ft x (33/4) ft x (7/2) ft
Volume = (33 x 33 x 7) / (2 x 4 x 2) cubic feet
Volume = (9,189) / (16) cubic feet
Volume = 573.06 cubic feet
3. Now that we have the volume in cubic feet, we can simplify it to a mixed number:
573.06 cubic feet = 573 cubic feet and 0.06 cubic feet
0.06 cubic feet can be expressed as 6/100 or 3/50 (simplified fraction)
Combining both parts, we get:
573 cubic feet + 3/50 cubic feet
573 3/50 cubic feet
Therefore, the pool can hold 573 3/50 cubic feet of water. Thank you for your patience.