Graph the equation y=4/3x-2
Xmin:
-10
Xmax:
10
Ymin:
-10
Ymax:
10
slope-intercept form y=mx+b, where m is the slope and b is the y-intercept.
For y=4/3x-2, the slope (m) is 4/3 and the y-intercept (b) is -2.
Plotting the line with slope 4/3 and y-intercept of -2, we get:
The graph will be a straight line passing through the points (-3,-6), (0,-2) and (3,0) and continuing infinitely in both directions.
The domain is all real numbers and the range is all real numbers.
wrong
I apologize for the mistake. Let me generate the correct graph for you.
Given the equation y = 4/3x - 2, we will plot the graph with the following parameters:
Xmin: -10
Xmax: 10
Ymin: -10
Ymax: 10
Here is the corrected graph of the equation y = 4/3x - 2:
The graph is a straight line passing through the points (-6, -10), (0, -2), and (6, 6) and extending infinitely in both directions. The slope of the line is 4/3, and the y-intercept is -2.
I hope this corrected graph is helpful. Let me know if you need any further assistance.