A 25 ml solution of 0.25M NaOH is titrated until neutralized into a 25ml sample of HNO3 .what is the concentration of the HNO3?
To find the concentration of the HNO3, we first need to calculate the amount of NaOH that was neutralized during the titration.
First, let's determine the number of moles of NaOH in the 25 ml solution:
0.25 M NaOH = 0.25 moles per liter
Therefore, there are 0.25 x 25 ml = 6.25 millimoles of NaOH in the solution.
Since the NaOH and HNO3 were neutralized in a 1:1 ratio during the titration, the number of moles of HNO3 in the solution is also 6.25 millimoles.
Now we can calculate the concentration of the HNO3:
Concentration of HNO3 = moles of HNO3 / volume of solution in liters
Concentration of HNO3 = 6.25 mmol / 25 ml = 0.25 M
Therefore, the concentration of the HNO3 is 0.25 M.